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# Minimum of Two Exponential

Suppose we want to simulate pseudo random numbers from the following distribution, which I came across in [r - Finding a way to simulate random numbers for this distribution - Cross Validated](https://stats.stackexchange.com/questions/391054/finding-a-way-to-simulate-random-numbers-for-this-distribution),

$$
F(x) = 1-\exp\left(-ax - \frac{b}{p+1}x^{p+1}\right),\quad x\ge 0
$$

where $$a, b>0$$ and $$p\in (0,1)$$.

[Xi'an](https://stats.stackexchange.com/users/7224/xian) provided a very elegant solution.

Note that

$$
(1-F(x))=\exp\left{-ax-\frac{b}{p+1}x^{p+1}\right}=\underbrace{\exp\left{-ax\right}}*{1-F\_1(x)}\underbrace{\exp\left{-\frac{b}{p+1}x^{p+1}\right}}*{1-F\_2(x)}
$$

the distribution $$F$$ is the distribution of

$$
X=\min{X\_1,X\_2}\qquad X\_1\sim F\_1,,X\_2\sim F\_2
$$

since

$$
F(x) = P(X\le x) = 1- P(X > x)  = 1-P(X\_1 > x)P(X\_2 > x) = 1-(1-F\_1(X))(1-F\_2(X)),.
$$

Thus, the R code to simulate is simple to be

```r
x = pmin(rexp(n, a), rexp(n, b/(p+1))^(1/(p+1)))
```

## References

* [Finding a way to simulate random numbers for this distribution](https://stats.stackexchange.com/questions/391054/finding-a-way-to-simulate-random-numbers-for-this-distribution)
* [simulation fodder for future exams](https://xianblog.wordpress.com/2019/02/20/simulation-fodder-for-future-exams/)


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